Case:
The operating system is: Winodws Server 2003 database: Oracle 10.0.2 SQL Server 2005 storage device is: IBM DS3200, 2, a total of 15 hard disks, each hard disk 1T capacity.One IBM DS3200 can only be connected to the hard disk and only connect to 12 hard disks, and the other IBM DS3200 is connected to three hard disks as the expansion cabinet. 15 hard disks make a set of RAID5. A total of one LUN is divided.Partition, the amount of data is about 5T.The entire RAID5 has a total of four hard disks offline, namely: No. 2, No. 3, No. 7, and No. 13 hard disks.
Solution:
The engineer conducted a low -level analysis of 15 hard disks. First of all, analyzed the No. 13 hard disk offline. The 15th hard disk was directly launched as a hot disk. According to the MBR information of No. 3 hard disk, the entire array partition size was: 13.04 T TIt is exactly the capacity of 14 hard disk RAID5, GPT partition. After different or detection, the No. 7 hard disk cannot be determined by analysis by analysis.RAID starts the sector: 212178 SEC. Remove No. 7 Hard Disk and No. 13 hard disk. Through the independent tools, directly virtually reorganize according to the described parameters, and directly see all the files of the partition.A total of 4.9TB data. The data file is directly restored to the new storage IBM DS5020 optical fiber storage provided by the customer.
